SOLUTION: solve trigonometric identity. Pick only one side to solve. tan^2x-sinx^2=sin^2xtan^2x

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Question 923963: solve trigonometric identity. Pick only one side to solve. tan^2x-sinx^2=sin^2xtan^2x
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
That should be properly written as tan%5E2%28x%29-sin%5E2%28x%29=sin%5E2%28x%29tan%5E2%28x%29.
As pure text, the expression is tan^2(x)-sin^2(x)=sin^2(x)tan^2(x)

Pick the left side to work with. The first step can be
%28sin%28x%29sin%28x%29%29%2F%28cos%28x%29cos%28x%29%29-sin%5E2%28x%29

sin%5E2%28x%29%2Fcos%5E2%28x%29-sin%5E2%28x%29

sin%5E2%28x%29%2Fcos%5E2%28x%29-sin%5E2%28x%29%28cos%5E2%28x%29%2Fcos%5E2%28x%29%29

%28sin%5E2%28x%29-sin%5E2%28x%29cos%5E2%28x%29%29%2Fcos%5E2%28x%29

sin%5E2%28x%29red%28%281-cos%5E2%28x%29%29%29%2Fcos%5E2%28x%29

Notice the opportunity for the simple circular pythagorean identity...

sin%5E2%28x%29red%28sin%5E2%28x%29%29%2Fcos%5E2%28x%29

.........!