SOLUTION: An isosceles triangle is inscribed in a circle with a 16-inch diameter. If the base of the triangle is a diameter of the circle, what is the area of the triangle?

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Question 900923: An isosceles triangle is inscribed in a circle with a 16-inch diameter. If the base of the triangle is a diameter of the circle, what is the area of the triangle?

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Two sides are equal, and the base side is 16 inches. The only way this fits in the circle as described is that the two equal sides meet at a right angle. The distance from circle center to the vertex opposite the base (the diameter serving as the base of the triangle) is a radius of the circle, 8 inches.

The area of this triangle is %281%2F2%29%2A16%2A8=64 square inches.