SOLUTION: Solve the given equation over the interval [0.2pi) sin^2(x)-(square root of 3)sin(x)+1= cos^2(x)

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Question 864111: Solve the given equation over the interval [0.2pi) sin^2(x)-(square root of 3)sin(x)+1= cos^2(x)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

interval [0 - 2pi)

sin^2(x)-√3sin(x)+1= cos^2(x)

(1-cos^2(x) -√3sin(x)+1= cos^2(x) 

√3sin(x)= 2(cos^2(x) - 1)

√3 sin(x)= -2sin^2(x)

 -√3 /2 = sin(x)  

See (c0sx, sinx) summary