SOLUTION: http://is.byu.edu/courses/hs/GEOM-043-101/secure/imgs/math10-196.gif
Find the range that gives all possible values for b.
a. 0 < b < 16
b. 1 < b < 16
Algebra ->
Triangles
-> SOLUTION: http://is.byu.edu/courses/hs/GEOM-043-101/secure/imgs/math10-196.gif
Find the range that gives all possible values for b.
a. 0 < b < 16
b. 1 < b < 16
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Question 764121: http://is.byu.edu/courses/hs/GEOM-043-101/secure/imgs/math10-196.gif
Find the range that gives all possible values for b.
a. 0 < b < 16
b. 1 < b < 16
c. 1 < b < 32
d. 0 < b < 32 Answer by solver91311(24713) (Show Source):
The measure of any side of a triangle must be strictly less than the sum of the measures of the other two sides. So b has to be strictly less than 16 + 16 and 16 has to be strictly less than 16 + b
John
My calculator said it, I believe it, that settles it
