SOLUTION: one leg of a right triangle is 5 mm longer than the shorter leg and the hypotenuse is 10 mm longer than the shorter leg. find the lengths of the sides of the triangle
Algebra ->
Triangles
-> SOLUTION: one leg of a right triangle is 5 mm longer than the shorter leg and the hypotenuse is 10 mm longer than the shorter leg. find the lengths of the sides of the triangle
Log On
Question 763827: one leg of a right triangle is 5 mm longer than the shorter leg and the hypotenuse is 10 mm longer than the shorter leg. find the lengths of the sides of the triangle Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Shorter leg = x
Longer leg = x + 5
Hypotenuse = x + 10
Pythagoras:
x^2 + (x + 5)^2 = (x + 10)^2
x^2 + x^2 + 10x + 25 = x^2 + 20x + 100
2x^2 + 10x + 25 = x^2 + 20x + 100
x^2 - 10x - 75 = 0
(x + 5)(x - 15) = 0
x + 5 = 0
x = -5 (no answer)
x - 15 = 0
x = 15
Shorter leg = 15mm
Longer leg = 20mm
Hypotenuse = 25mm
Hope this helps.
:-)
