SOLUTION: a photographer shines a camera light at a particular painting forming an angle of 47 degrees with the camera platform. if the light is 52 feet from the wall where the painting hang
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Question 756353: a photographer shines a camera light at a particular painting forming an angle of 47 degrees with the camera platform. if the light is 52 feet from the wall where the painting hangs, how high above the platform is the painting? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a photographer shines a camera light at a particular painting forming an angle of 47 degrees with the camera platform. if the light is 52 feet from the wall where the painting hangs, how high above the platform is the painting?
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Draw the picture.
You have a right triangle with base angle = 47 degrees and hypotenuse = 52 ft
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Height/hypotenuse = sin(47)
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height = 52*sin(47) = 38.03 ft.
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Cheers,
Stan H.
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