SOLUTION: What is the perimeter and area of a 45°-45°-90° triangle with a hypotenuse length of 12 feet?

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Question 751248: What is the perimeter and area of a 45°-45°-90° triangle with a hypotenuse length of 12 feet?
Answer by reviewermath(1029) About Me  (Show Source):
You can put this solution on YOUR website!
In a 45°-45°-90° triangle, the length of the hypotenuse is equal to sqrt%282%29 times the length of the leg.
If hypotenuse = 12 feet, then the length of each leg is 12%2Fsqrt%282%29 ft = 6sqrt%282%29 ft.
Perimeter = 12 + 2%286sqrt%282%29%29 ft = highlight%2812+%2B+12sqrt%282%29%29 ft
Area = Square the length of the leg then divide by 2
= %28%286sqrt%282%29%29%5E2%29%2F2 sq ft = highlight%2836%29 sq ft