SOLUTION: triangle QRS has vertices at Q(2,6),R(-3,1), and S(6,2). determine the perimeter of the triangle. i just need help how to do it. thnxs

Algebra ->  Triangles -> SOLUTION: triangle QRS has vertices at Q(2,6),R(-3,1), and S(6,2). determine the perimeter of the triangle. i just need help how to do it. thnxs      Log On


   

Question 720981: triangle QRS has vertices at Q(2,6),R(-3,1), and S(6,2). determine the perimeter of the triangle. i just need help how to do it. thnxs
Found 2 solutions by josgarithmetic, fcabanski:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Distance formula to find QR, RS, and QS; and then find the sum of those segment lengths.

Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a triangle is the sum of the side lengths. The distance formula gives the distance between points on a coordinate plane. The distance between pairs of points (vertices) in a triangle is the side length.


The distance formula is the square root of the difference between the y values squared plus the difference between the x values squared.


d=sqrt%28%28y%282%29-y%281%29%29%5E2+%2B+%28x%282%29-x%281%29%29%5E2%29


The triangle has three sides: QR, RS and SQ. Find the lengths of those sides, then add them to find the perimeter.


QR length = d = sqrt%28%281-6%29%5E2+%2B+%28-3-2%29%5E2%29+=+sqrt%2850%29


RS length = d = sqrt%28%282-1%29%5E2+%2B+%286-%28-3%29%29%5E2%29+=+sqrt%2882%29


SQ length = d = sqrt%28%286-2%29%5E2+%2B+%282-6%29%5E2%29+=+sqrt%2832%29


Their sum is approximately 21.78

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