SOLUTION: Quadrilateral ABCD is in the shape of a kite. AB and AD are both 2 feet. BC and BC are both 3 feet. There is a line from A to C and another line from B to D. AC is 4 feet. What is

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Question 70570: Quadrilateral ABCD is in the shape of a kite. AB and AD are both 2 feet. BC and BC are both 3 feet. There is a line from A to C and another line from B to D. AC is 4 feet. What is the measure of the angle the 2-foot edge makes with the 3-foot edge?
Found 2 solutions by venugopalramana, ikleyn:
Answer by venugopalramana(3286)   (Show Source):
You can put this solution on YOUR website!
Quadrilateral ABCD is in the shape of a kite. AB and AD are both 2 feet. BC and BC are both 3 feet. There is a line from A to C and another line from B to D. AC is 4 feet. What is the measure of the angle the 2-foot edge makes with the 3-foot edge?
AB=AD=2
BC=BD=3
AC=4
TO FIND ANGLE ABC=X SAY
IN TRIANGLE ABC
AC^2=AB^2+BC^2-2AB*BC*COS[X]
COS(X)=[4^2-2^2-3^2]/[2*2*3]=3/12=1/4
X=ANGLE ABC= 75.5 DEGREES

Answer by ikleyn(54062)   (Show Source):
You can put this solution on YOUR website!
.
Quadrilateral ABCD is in the shape of a kite. AB and AD are both 2 feet.
BC and BD are both 3 feet.
There is a line from A to C and another line from B to D. AC is 4 feet.
What is the measure of the angle the 2-foot edge makes with the 3-foot edge?
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        There is an error in calculations in the post by @venugopalramana, so his solution is erroneous.
        I came to bring a correct solution.

        Notice that I edited an obvious typo in the post to make sense from nonsense. My editing is in red.

AB=AD=2
BC=BD=3
AC=4
TO FIND ANGLE ABC=X SAY
IN TRIANGLE ABC
AC^2 = AB^2+BC^2-2AB*BC*COS[X]
COS(X) = [2^2+3^2-4^2]/[2*2*3] = -3/12 = -1/4
X = ANGLE ABC = 104.48 DEGREES (approximately).         ANSWER

Solved correctly.