Question 69726: Alright, i have a Right triangle (ABC) and im doing a some basic trig, such as sine cosine and tangent. angle C is 72 deg, angle B is 90, BC is 5, and AB is app 15.39. using either tan, cos or sin, i have to find the hypotenuse, the problem is i was never taught how to solve with the variable on the bottom. how do i do it. please do not simply give me the answer because it is homework and that wouldnt be right. if you caould help tha'd be great.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! angle C is 72 deg, angle B is 90, BC is 5, and AB is app 15.39. using either tan, cos or sin, i have to find the hypotenuse,
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Draw and picture; label the angle and side values.
You say AB is approximately 15.39; if that is its
actual value sin72 = 15.39/hyp
Then hyp = 15.39/sin72
hyp = 16.18...
Cheers,
Stan H.
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