SOLUTION: The perimeter of a rectangular painting is 290 centimeters. If the width of the painting is 62 centimeters, what is its length?

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Question 598274: The perimeter of a rectangular painting is 290 centimeters. If the width of the painting is 62 centimeters, what is its length?
Answer by math-vortex(648) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, there--
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The PERIMETER P is the distance around the rectangle.
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Let's call the width of the rectangle W and the length of the rectangle L.
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As you go around the edge there two equal lengths and two equal widths. The formula for the perimeter of a rectangle is P=2*L+2*W.
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P=2L%2B2W
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Substitute 290 for P and 62 for the width.
290=2L%2B2%2862%29
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Solve for L.
290=2L%2B2%2862%29
290=2L%2B124
290-124=2L
2L=166
L=83
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The equation L=83 means that the length is 83 cm.
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CHECK your work.
2(62)+2(83) = 124+166 = 290cm.
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The length of the rectangle is 83cm.
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That's it! Feel free to email via gmail if the solution is unclear.
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Ms.Figgy
math.in.the.vortex@gmail.com