SOLUTION: The length of a rectangle is 6 feet less than twice the width. The perimeter is 48 feet. Find the length and width

Algebra ->  Triangles -> SOLUTION: The length of a rectangle is 6 feet less than twice the width. The perimeter is 48 feet. Find the length and width      Log On


   



Question 570923: The length of a rectangle is 6 feet less than twice the width. The perimeter is 48 feet. Find the length and width
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
length(l) width(w) perimeter(p)
given:
l=2w-6
p=48
2l%2B2w=p
.
2%282w-6%29%2B2w=48 solve for w
4w-12%2B2w=48
6w=60
w=10
.
l=2w-6
l=2%2810%29-6
l=14