SOLUTION: Two ships leave from the same location with an angle of 57 degrees between their path. If ship A travels at 36 kph and ship B travels at 42 kph , how far apart are they after 1/2 h
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Question 550181: Two ships leave from the same location with an angle of 57 degrees between their path. If ship A travels at 36 kph and ship B travels at 42 kph , how far apart are they after 1/2 hour ? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Two ships leave from the same location with an angle of 57 degrees between their path.
If ship A travels at 36 kph and ship B travels at 42 kph , how far apart are they after 1/2 hour?
:
Find the distance each ship will travel in .5 hrs
Ship A: 36*.5 = 18 km
Ship B: 42*.5 = 21 km
:
This is side/angle/side. Use the law of cosines: a^2 = b^2 + c^2 - 2bc*cos(A)
Where
a = side opposite angle 57 degrees (distance between the ships)
A = 57 degrees
b = 21
c = 18
:
a^2 = 21^2 + 18^2 - 2(18*21)*cos(57)
a^2 = 441 + 324 - 2(378*.54464)
a^2 = 765 - 411.75
a^2 = 353.25
a =
a = 18.8 km apart after a half hour
