SOLUTION: in a right angled triangle if one of the acute angle is twicethe other,prove that the hypotenuse is double the side opposite to smallest angle.

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Question 500861: in a right angled triangle if one of the acute angle is twicethe other,prove that the hypotenuse is double the side opposite to smallest angle.
Answer by cleomenius(959) About Me  (Show Source):
You can put this solution on YOUR website!
x + 2x + 90 = 180
3x = 90
x = 30 degrees, the smallest angle.
sin(30) = opp/hyp
1/2 = x/hyp
hyp = 2 * x.
Cleomenius.