Question 491577: How do you find the height of triangle whose base is 44cm and sides Are 38cm and 30cm?
Found 2 solutions by cleomenius, lwsshak3: Answer by cleomenius(959) (Show Source): Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! How do you find the height of triangle whose base is 44cm and sides Are 38cm and 30cm?
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Draw a triangle with the apex labeled, A, the angle on the left, B and the the angle on the right, C. Draw a line from the apex down to where it intersects the base BC. Call this line h=height and label the point of intersection as D. The base is divided into two parts. Call the left part x, and the right part (44-x). We now have two right triangles to work with, ACD and ABD, and sides AB=38, AC=30, BC=44.
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Using Pythagorean Theorem:
AB^2-h^2=x^2
38^2-h^2=x^2
h^2=38^2-x^2
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AC^2-h^2=(44-x)^2
30^2-h^2=44^2-88x+x^2
sub h^2
30^2-38^2+x^2=44^2-88x+x^2
900-1444=1936-88x
-2480=-88x
x=2480/88=28.18
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h^2=38^2-x^2=1444-28.18^2=649.79
h=√649.79=25.49 cm
ans:
Height of triangle=25.49 cm
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