SOLUTION: Find the value of x. A 30, 60, 90 degree right triangle is drawn. The 60 degree angle is labeled. The shortest leg adjacent to the 60 degree angle is labeled x. The longest leg op

Algebra ->  Triangles -> SOLUTION: Find the value of x. A 30, 60, 90 degree right triangle is drawn. The 60 degree angle is labeled. The shortest leg adjacent to the 60 degree angle is labeled x. The longest leg op      Log On


   

Question 466177: Find the value of x.
A 30, 60, 90 degree right triangle is drawn. The 60 degree angle is labeled. The shortest leg adjacent to the 60 degree angle is labeled x. The longest leg opposite the 60 degree angle is labeled 5 times the square root of 3. The hypotenuse is labeled y.
Answer by stanbon(75887) About Me  (Show Source):
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Find the value of x.
A 30, 60, 90 degree right triangle is drawn. The 60 degree angle is labeled. The shortest leg adjacent to the 60 degree angle is labeled x. The longest leg opposite the 60 degree angle is labeled 5 times the square root of 3. The hypotenuse is labeled y.
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side opposite 30 degree angle = x
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therefore hypotenuse = y = 2x
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Pythagoras:
x^2 + (2x)^2 = (5sqrt(3))^2
x^2 + 4x^2 = 75
5x^2 = 75
x^2 = 15
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x = sqrt(15)
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Cheers,
Stan H.
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