SOLUTION: The rim of a basketball hoop is 10 feet above the ground. The free-throw line is 15 feet from the rim of the basket. If the eyes of a basketball player are 6 feet above the ground,

Question 447052: The rim of a basketball hoop is 10 feet above the ground. The free-throw line is 15 feet from the rim of the basket. If the eyes of a basketball player are 6 feet above the ground, what is the angle of elevation of the player's line of sight when shooting a free throw to the rim of the basket?

please show all work so i can understand better
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The rim of a basketball hoop is 10 feet above the ground. The free-throw line is 15 feet from the rim of the basket. If the eyes of a basketball player are 6 feet above the ground, what is the angle of elevation of the player's line of sight when shooting a free throw to the rim of the basket?
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Draw the picture.
You have a right triangle with base = 15 ft
and height = (10-6) = 4 ft
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The angle of elevation is tan^-1(4/15) = 14.93 degrees.
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Cheers,
Stan H.

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