SOLUTION: In a right triangle, one leg is 2 cm longer than the other leg, and the hypotenuse is twice as long as the shorter leg. Find the lengths of each of the three sides of the triangle.

Algebra ->  Triangles -> SOLUTION: In a right triangle, one leg is 2 cm longer than the other leg, and the hypotenuse is twice as long as the shorter leg. Find the lengths of each of the three sides of the triangle.      Log On


   

Question 433608: In a right triangle, one leg is 2 cm longer than the other leg, and the hypotenuse is twice as long as the shorter leg. Find the lengths of each of the three sides of the triangle.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let one leg be x
otehr leg = x+2
hypotenuse = 2x
x^2+(x+2)^2=(2x)^2
x^2+x^2+4x+4=4x^2
2x^2-4x-4=0
Find the roots of the equation by quadratic formula
a=2 b= -4 c= -4

b^2-4ac=16 + 32
b^2-4ac=48 sqrt%2848%29= 6.93
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=(4+6.93)/4
x1= 2.73
x2=(4-6.93)/4
x2=-0.73
Ignore negative value
shortleg = 2.73 cm
longer leg = 4.73 cm
hypotenuse = 5.46cm