SOLUTION: 1.) If a triangle has sides of lengths 5, 12, and 13, is the triangle right? 2.) Refer to right triangle ACB. If BC = 5 and AB = 6, what is AC in simplified form? 3.) Refer to

Algebra ->  Triangles -> SOLUTION: 1.) If a triangle has sides of lengths 5, 12, and 13, is the triangle right? 2.) Refer to right triangle ACB. If BC = 5 and AB = 6, what is AC in simplified form? 3.) Refer to       Log On


   



Question 411076: 1.) If a triangle has sides of lengths 5, 12, and 13, is the triangle right?
2.) Refer to right triangle ACB. If BC = 5 and AB = 6, what is AC in simplified form?
3.) Refer to Triangle DFE. If DM = 4 and ME = 9, what is FM in simplified form?
4.) Refer to Triangle DFE. If DM = 6 and DE = 18, what is FM in simplified form?

5.) Refer to right triangle ACB. If AC = 6 and BC = 8, what is AB in simplified form?

6.) Refer to right triangle ACB. If AC = 4 and AB = 5, what is BC in simplified form?

Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
If a triangle has sides 5, 12, 13, it is a right triangle since 5%5E2+%2B+12%5E2+=+13%5E2.

For the other five problems, use the Pythagorean theorem: a%5E2+%2B+b%5E2+=+c%5E2 where c is the hypotenuse and a,b are the lengths. I'll let you do these problems with the hint I've provided. If one of your provided lengths is the hypotenuse you'll have to rearrange the variables, i.e. a%5E2+=+c%5E2+-+b%5E2, etc.