SOLUTION: i have several questions..... Classify each triangle (acute, obtuse, right) based on the given side lengths. 1) 6,9,10 2) 18,24,30 3) 20,100,110 4) 7,24,25 5) 2,5,6 6) 13,21

Algebra ->  Triangles -> SOLUTION: i have several questions..... Classify each triangle (acute, obtuse, right) based on the given side lengths. 1) 6,9,10 2) 18,24,30 3) 20,100,110 4) 7,24,25 5) 2,5,6 6) 13,21      Log On


   



Question 357621: i have several questions.....
Classify each triangle (acute, obtuse, right) based on the given side lengths.
1) 6,9,10
2) 18,24,30
3) 20,100,110
4) 7,24,25
5) 2,5,6
6) 13,21,24 (if you could, could you explain how to do this?)
&&
Find the area of the shaded region. leave answers in simplest radical form
1) (isosceles) b= 40 in. side= 29 in.
2) (isosceles) b= 12 cm side=14 cm
3) (isosceles) b= 70 ft. side= 41 ft.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Classify each triangle (acute, obtuse, right) based on the given side lengths.
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Let "c" be the longest side on each set of three numbers.
If c^2 = a^2+b^2, the triangle is right
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If c^2 > a^2 + b^2, the triangle is obtuse
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If c^2 < a^2 + b^2, the triangle is acute.
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1) 6,9,10
Example:
10^2 R 6^2 + 9^2
100 R 36+81
100 < 117
Therefore the triangle is acute.
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Use the same process on #2 thru #6:
2) 18,24,30
3) 20,100,110
4) 7,24,25
5) 2,5,6
6) 13,21,24
Cheers,
Stan H.