SOLUTION: I do not know how to set up this problem. Can anyone help me?
Two frames are needed with the same outside perimeter: one frame in the shape of a square and one in the shape of a
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-> SOLUTION: I do not know how to set up this problem. Can anyone help me?
Two frames are needed with the same outside perimeter: one frame in the shape of a square and one in the shape of a
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Question 343290: I do not know how to set up this problem. Can anyone help me?
Two frames are needed with the same outside perimeter: one frame in the shape of a square and one in the shape of an equilateral triangle. Each side of the triangle is 6 centimeters longer than each side of the square. Find the dimensions of each frame. Found 2 solutions by nerdybill, scott8148:Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! Two frames are needed with the same outside perimeter: one frame in the shape of a square and one in the shape of an equilateral triangle. Each side of the triangle is 6 centimeters longer than each side of the square. Find the dimensions of each frame.
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Let x = length of one side of the square (in cm)
then
x+6 = length of one side of the triangle
.
Perimeter of square is 4x
perimeter of triangle is 3(x+6)
.
So:
4x = 3(x+6)
4x = 3x+18
x = 18 centimeters
and
Length of one side of triangle:
x+6 = 18+6 = 24 centimeters
.
Dimensions of square: 18 by 18 by 18 by 18 (centimeters)
Dimensions of triangle: 24 by 24 by 24 (centimeters)
