SOLUTION: In triangle RST, RS= 2x+10, ST = 3x-2 and RT = (1/2)x +28. if triangle is equiangular, what is the value of x ?
A 2 B 5 1/3 C 6 D 12 E 34
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-> SOLUTION: In triangle RST, RS= 2x+10, ST = 3x-2 and RT = (1/2)x +28. if triangle is equiangular, what is the value of x ?
A 2 B 5 1/3 C 6 D 12 E 34
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Question 328543: In triangle RST, RS= 2x+10, ST = 3x-2 and RT = (1/2)x +28. if triangle is equiangular, what is the value of x ?
A 2 B 5 1/3 C 6 D 12 E 34 Answer by nyc_function(2741) (Show Source):
You can put this solution on YOUR website! If the triangle is equiangular, then all sides must be the same length.
Equate any two sides that you like and solve for x.
I will equate 2x + 10 to 3x - 2.
2x + 10 = 3x - 2
2x - 3x = -2 - 10
-x = -12
x = -12/-1
x = 12
CHOICE D is correct.
