SOLUTION: i have an isosceles triangle. One angle has 3x and the other angle has (x+50). How to find the third angle

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Question 260312: i have an isosceles triangle. One angle has 3x and the other angle has (x+50).
How to find the third angle

Found 3 solutions by drk, stanbon, edjones:
Answer by drk(1908) About Me  (Show Source):
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There are two options here.
option 1 - base angles = 3x and non base angle = x+50.
all angles add to 180, so we get
3x+%2B+3x+%2B+x%2B50+=+180
7x+%2B+50+=+180
7x+=+130
x+=+18.57
which means two angles are: 55.714 and the last angle is: 68.57
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option 2 - base angles = x+50 and non base angle = 3x.
all angles add to 180, so we get
3x+%2B+x%2B50+%2B+x%2B50+=+180
5x+%2B+100+=+180
5x+=+80
x+=+16
which means two angles are: 66 and the last angle is: 48
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Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
i have an isosceles triangle. One angle has 3x and the other angle has (x+50).
How to find the third angle.
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That depends on which of the two you listed is one of the equal angles.
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If 3x is paired with another 3x you get:
3x + 3x + x+50 = 180
7x = 130
x = 130/7
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3x = 390/7
x+50 = (130/7) + (350/7) = 480/7
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If (x+50) is paired with another (x+50) you get:
2(x+50) + 3x = 180
5x = 80
x = 16 degrees
3x = 48
x+50 = 66 degrees.
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Comment:
Judging from those answer I would guess the x+50
is one of the two equal angles.
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Cheers,
Stan H.

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
Are the 2 given angles equal?