SOLUTION: I need step by step help on how to solve this problem: The area of a triangle is 16 inches more than the base. If the height is 6 inches, what is the length of the base? I can f

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Question 258848: I need step by step help on how to solve this problem:
The area of a triangle is 16 inches more than the base. If the height is 6 inches, what is the length of the base? I can find the answer, but I need to know the steps involved.
Thanks!
Found 2 solutions by CharlesG2, drk:
Answer by CharlesG2(834) (Show Source):
You can put this solution on YOUR website!
I need step by step help on how to solve this problem:
The area of a triangle is 16 inches more than the base. If the height is 6 inches, what is the length of the base? I can find the answer, but I need to know the steps involved.
Thanks!
Area A of a triangle is 1/2 * B base * H height
area is measured in square inches (in^2) not in inches
if H=6 inches then you have A=1/2*B*6 or A=3*B and 1/3*A=B
if you mean to plug B+16 in for A then you would get 1/3*(B+16)=B
1/3*B + 16/3 = B
16/3 = B - 1/3*B
16/3 = 2/3 * B
14/3 = B
plugging in 14/3 for B and 6 inches for H
you get A = 1/2*14/3*6 = 3 * 14/3 = 14
Hope this is what you are looking for and that this helps.

Answer by drk(1908) (Show Source):
You can put this solution on YOUR website!
Are of triangle is expressed as
(i)
since area is 16 more than base, we get
(ii)
Also, h = 6, so we
get

solving we get

This is a weird answer:
--
check
A = (1/2)bh
A = (1/2)(10.666)(5)
A = 26.6666
A = B + 16.