Question 253407: i have two questions that i really need help with, help would be very appreciated.
1. A parcel of land is in the shape of an isosceles triangle. the base had a length of 673 feet and the two equal legs meet an angle of 43 degrees. Find, to the nearest square foot, the area of the parcel of land.
i know that area equals one half base times height but i have no idea how to figure out the height i dont know if i should cut the triangle in half or what.
2. The triangle top of a table has two sides of 14 inches and 16 inches and the angle between the sides is 30 degrees. Find the area of the tabletop, in square inches.
i drew i diagram and have attepmted several ways but none of the answers makes sense should i use sohcahtoa i desperatley need help.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! 1. A parcel of land is in the shape of an isosceles triangle. the base had a length of 673 feet and the two equal legs meet an angle of 43 degrees. Find, to the nearest square foot, the area of the parcel of land.
The other 2 angles are 68.5º.
The tan(68.5) = h/(base/2)
h = tan(68.5)*b/2 = tan(68.5)*336.5
h =~854.255
Area = bh/2 = 143728.4 sq feet
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2. The triangle top of a table has two sides of 14 inches and 16 inches and the angle between the sides is 30 degrees. Find the area of the tabletop, in square inches.
Call the 16" side the base.
h = 14*sin(30) = 7
Area = bh/2 = 16*7/2 = 56 sq in
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