SOLUTION: Happy holidays. I am having trouble with this question and i think it should be in this section. Please help me. I am so lost. heres the link http://www2.edmastery.com/li/itemAs

Algebra ->  Triangles -> SOLUTION: Happy holidays. I am having trouble with this question and i think it should be in this section. Please help me. I am so lost. heres the link http://www2.edmastery.com/li/itemAs      Log On


   

Question 251891: Happy holidays.
I am having trouble with this question and i think it should be in this section. Please help me. I am so lost.
heres the link
http://www2.edmastery.com/li/itemAssets/NN.MAT.301307.1.HO%2Fres00016%2F21fc5023cb6e448e87f4efd448374370%2FUnit3question2.jpg
Found 2 solutions by jim_thompson5910, Edwin McCravy:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
It's not stated, but there is another fact about this figure that HK = HK. Since IK = JH and HI = KJ also, we have 3 pairs of congruent sides which means that SSS will be used in this case.

Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!

The correct choice is [A] because 

IK is congruent to JH is given,
HI is congruent to KJ is given,
and
HK is congruent to HK by the
reflexive property

That makes the three corresponding sides of the two triangles
congruent.  That's the "side-side-side" theorem.

Edwin