SOLUTION: Find the value of x and then classify the triangles. pg. 174 20x+10, 30x -2, 7x+1 I was thinking that I had to add 20x+30x+7x= 57x Then 10-2+1=9 57x+9=360 57x=351

Algebra ->  Triangles -> SOLUTION: Find the value of x and then classify the triangles. pg. 174 20x+10, 30x -2, 7x+1 I was thinking that I had to add 20x+30x+7x= 57x Then 10-2+1=9 57x+9=360 57x=351       Log On


   

Question 166330: Find the value of x and then classify the triangles. pg. 174
20x+10, 30x -2, 7x+1
I was thinking that I had to add
20x+30x+7x= 57x
Then
10-2+1=9
57x+9=360
57x=351
It is just not coming out right. So frustrated!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Its hard to know what you are doing without the full instructions and what "20x+10, 30x -2, 7x+1 " are referring to (are these side lengths? angles?)

However, since I'm seeing a "360" I'm assuming that you are working with angles.

There's a problem though: ALL angles in a triangle add to 180 degrees (not 360 degrees). So the equation should be:


%2820x%2B10%29%2B%2830x+-2%29%2B%287x%2B1%29=180


Let me know if you still need help.


Note: the answer is x=3 and the three angles are 70, 88, and 22