SOLUTION: The longest side of a triangle measured 267m,if two angles are 37and 48,find the shortest side of the triangle
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-> SOLUTION: The longest side of a triangle measured 267m,if two angles are 37and 48,find the shortest side of the triangle
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To find out which is the longest side, we use the fact that
the longest side is opposite the largest angle. Two of the
angles are given as 37o and 48o, so the third angle is
180o-(37o+48o) = 180o-85o = 95o.
So the longest side is opposite the 95o angle. We want to
find the shortest side. We use the fact that the shortest
side is opposite the smallest angle. So it's the side
opposite the 37o-angle, which we will call x. Here is how
the triangle looks, drawn approximately to scale:
We use the law of sines
Cross-multiply:
Since the given side is rounded to 3 significant digits,
we round that to 161m.
Edwin
The given angles are
A = 37 degrees
B = 48 degrees
Let's find angle C
A+B+C = 180
C = 180-A-B
C = 180-37-48
C = 95 degrees
The interior angles of the triangle are
A = 37 degrees
B = 48 degrees
C = 95 degrees
The shortest side is opposite the smallest angle.
The longest side is opposite the largest angle.
Since C = 95 is the largest angle, we have c = 267 as the longest side.
Side 'a' is the shortest side, opposite the smallest angle (A = 37)
Diagram
Use the law of sines to determine 'a'.
sin(A)/a = sin(C)/c
sin(37)/a = sin(95)/267
267*sin(37) = a*sin(95)
a*sin(95) = 267*sin(37)
a = 267*sin(37)/sin(95)
a = 161.298400292027
a = 161.2984
The shortest side is approximately 161.2984 meters long.
Round this value however your teacher instructs.
Make sure your calculator is in degree mode.