SOLUTION: Lines drawn parallel to the base of the triangle pictured, separate the other two sides into 10 equally spaced parts. What percentage of the triangle is grey?

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Question 1198962: Lines drawn parallel to the base of the triangle pictured, separate the other two sides into 10 equally spaced parts. What percentage of the triangle is grey?
Found 3 solutions by Alan3354, lotusjayden, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
pictured where?

Answer by lotusjayden(18) About Me  (Show Source):
You can put this solution on YOUR website!
The image is here
.

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
The area of the k-th triangle is  %28k%2F10%29%5E2  of the area of the greatest triangle, A.


Therefore, the area of k-th individual single shape is  

    %28k%2F10%29%5E2 - %28%28k-1%29%2F10%29%5E2  of the area of greatest triangle, A,    (1)

or

    a%5Bk%5D = %281%2F100%29%2A%28k%5E2+-+%28k%5E2-2k%2B1%29%29%2AA = %281%2F100%29%282k-1%29%2AA.    (2)



From here, the area of the grey part is

    A(grey) = %281%2F100%29%2A%281+%2B+5+%2B+9+%2B+13+%2B+17%29%2AA = %2845%2F100%29%2AA.      (3)

(summing all (2k-1) over k = 1, 3, 5, 7, 9)



The area of the unshaded (white) part is

    A(white) = %281%2F100%29%2A%283+%2B+7+%2B+11+%2B+15+%2B+19%29 = %2855%2F100%29%2AA.    (4)

(summing all (2k-1) over k = 2, 4, 6, 8, 10)



Therefore,  the ratio under the problem's question is

    A%28grey%29%2FA%28white%29 = 45%2F55 = 9%2F11.    ANSWER

Solved.

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Surely, one can avoid calculating unshaded area (4), when the area of grey part (3) is just calculated.

I did it only for the purpose of completeness.