SOLUTION: in the diagram AB = 2CB. the ratio of the area of the square to the area of triangle ABC is
https://drive.google.com/file/d/1OLoNfOQimyKibR2ZeSMbdlu-oaWReT8h/view?usp=sharing
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-> SOLUTION: in the diagram AB = 2CB. the ratio of the area of the square to the area of triangle ABC is
https://drive.google.com/file/d/1OLoNfOQimyKibR2ZeSMbdlu-oaWReT8h/view?usp=sharing
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Question 1186236: in the diagram AB = 2CB. the ratio of the area of the square to the area of triangle ABC is
https://drive.google.com/file/d/1OLoNfOQimyKibR2ZeSMbdlu-oaWReT8h/view?usp=sharing Answer by greenestamps(13198) (Show Source):
BFDE is a square, so triangles AED, ABC and DFC are similar.
So DF = 2*FC.
Then, since DF=FB...
Let CF = x. Then...
DF = 2x
BC = CF+FB = CF+DF = x+2x = 3x
AB=2*BC = 6x
That gives you all the measurements you need to find the areas of all of the figures in the diagram in terms of x; then you will be able to answer the question.
