You can put this solution on YOUR website! Solve the triangle a=4 b=3 c=6
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a^2 = b^2+c^2-2bc*Cos(A)
Let A be the angle opposite a = 4
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Then::
Cos(A) = [4^2 - 3^2-6^2]/(-2*3*6) = 0.8056
A = arcCos(0.8056) = 36.33 degrees
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Do the same with B.
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Then C = 180-(A+B)
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Cheers,
Stan H.
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