SOLUTION: the sum of the acute angles of an obtuse triangle is 70° and their difference is 10° .then what is its largest angle?
Algebra ->
Triangles
-> SOLUTION: the sum of the acute angles of an obtuse triangle is 70° and their difference is 10° .then what is its largest angle?
Log On
Question 1039921: the sum of the acute angles of an obtuse triangle is 70° and their difference is 10° .then what is its largest angle? Found 2 solutions by josmiceli, MathTherapy:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = the largest angle
given:
Add these equations
and
----------------
Also, the sum of the angles of a triangle
= , so
The largest angle is 110 degrees
You can put this solution on YOUR website! the sum of the acute angles of an obtuse triangle is 70° and their difference is 10° .then what is its largest angle?
Too much info. given! If one or both acute angles were required, then all given information would be pertinent.
Let the largest (obtuse) angle be L, and smaller of acute angles, S
Then larger of acute angles = 70 – S
We then get: L + S + 70 – S = 180
L, or largest (obtuse) angle = 180 – 70, or
OR
Largest + sum of other 2 angles = 180
L + 70 = 180
L, or largest (obtuse) angle = 180 – 70, or
