SOLUTION: find the perimeter of triangle ABC where A(-4,-1) B(4,5) and C(4,-2)

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Question 1037610: find the perimeter of triangle ABC where A(-4,-1) B(4,5) and C(4,-2)
Answer by jhunjiro(67) About Me  (Show Source):
You can put this solution on YOUR website!
To get the Perimeter you need to get the distance between two points
then add them
Perimeter of Triangle = a+b+c
a=AB
b=BC
c=AC
distance formula for two points
d+=sqrt%28+%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%29+
AB=sqrt((x2-x1)^2+(y2-y1)^2)
AB=sqrt((4--4)^2+(5--1)^2)
AB=sqrt(64+36)
AB=sqrt(100)
AB=10
-----------
BC=sqrt((x2-x1)^2+(y2-y1)^2)
=sqrt((4-4)^2+(-2-5)^2)
=sqrt(0+49)
=sqrt(49)
=7
--------------
AC=sqrt((x2-x1)^2+(y2-y1)^2)
=sqrt((4--4)^2+(-2--1)^2)
=sqrt(64+1)
=sqrt(65)
=8.06225774829855
=8.0623
-------------------------------
perimeter = 10+7+8.0623
P= 25.0623