SOLUTION: The perimeter of a certain rectangle is no more than 106 feet. If the length is eleven feet more than the width, what is the width?

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Question 1009009: The perimeter of a certain rectangle is no more than 106 feet. If the length is eleven feet more than the width, what is the width?
Found 2 solutions by fractalier, ikleyn:
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Perimeter P = 2L + 2W <= 106 and we also have
L = W + 11...now substitute and get
2(W + 11) + 2W <= 106
2W + 22 + 2W <= 106
4W + 22 <= 106
4W <= 84
W <= 21 feet

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
The perimeter of a certain rectangle is no more than 106 feet.
If the length is eleven feet more than the width, what is the width?
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You need to solve an inequality for the width w:

2*w + 2*(w+11) <= 106.

4w + 22 <= 106,

4w <= 106 - 22 = 84.

w <= 84%2F4 = 21 ft.

Answer. w <= 21 ft.