Tutors Answer Your Questions about Systems-of-equations (FREE)
Question 57313: 2. There were 1500 people at a high school football game. Student tickets were $2.00 and adult tickets were $3.50. The total receipts for the game were $3825. How many students bought tickets?
Let a = the number of adult tickets purchased.
Let s = the number of student tickets purchased.
. Write a system of equations that can be used to determine the number of adult and student tickets purchased.
. Determine the number of adults tickets sold and the number of student tickets sold. Use mathematics to explain how you determined your answer.
Click here to see answer by aaaaaaaa(138) |
Question 57316: 4. Your family likes to go to baseball games. At one game your family bought 5 soft drinks and 5 hot dogs for $22.25. At the next game your family attended they bought 4 soft drinks and 3 hot dogs for $14.50. What is the cost of one soft drink and one hot dog?
Let s = the cost of one soft drink
Let h = the cost of one hot dog
Write a system of equations modeling the situation described above.
Solve the system for the cost of one soft drink + one hot dog. (You will have to add your solutions together for this one.)
Click here to see answer by CrazyMan Jr.(21) |
Question 57316: 4. Your family likes to go to baseball games. At one game your family bought 5 soft drinks and 5 hot dogs for $22.25. At the next game your family attended they bought 4 soft drinks and 3 hot dogs for $14.50. What is the cost of one soft drink and one hot dog?
Let s = the cost of one soft drink
Let h = the cost of one hot dog
Write a system of equations modeling the situation described above.
Solve the system for the cost of one soft drink + one hot dog. (You will have to add your solutions together for this one.)
Click here to see answer by stanbon(75887) |
Question 57328: There were 1500 people at a high school football game. Student tickets were $2.00 and adult tickets were $3.50. The total receipts for the game were $3825. How many students bought tickets?
Let a = the number of adult tickets purchased.
Let s = the number of student tickets purchased. Write a system of equations that can be used to determine the number of adult and student tickets purchased.
Determine the number of adults tickets sold and the number of student tickets sold.
Click here to see answer by CrazyMan Jr.(21) |
Question 57328: There were 1500 people at a high school football game. Student tickets were $2.00 and adult tickets were $3.50. The total receipts for the game were $3825. How many students bought tickets?
Let a = the number of adult tickets purchased.
Let s = the number of student tickets purchased. Write a system of equations that can be used to determine the number of adult and student tickets purchased.
Determine the number of adults tickets sold and the number of student tickets sold.
Click here to see answer by funmath(2933) |
Question 57328: There were 1500 people at a high school football game. Student tickets were $2.00 and adult tickets were $3.50. The total receipts for the game were $3825. How many students bought tickets?
Let a = the number of adult tickets purchased.
Let s = the number of student tickets purchased. Write a system of equations that can be used to determine the number of adult and student tickets purchased.
Determine the number of adults tickets sold and the number of student tickets sold.
Click here to see answer by stanbon(75887) |
Question 57326: . Suppose you just have just enough dimes and quarters to pay for a loaf of bread and quart of milk, which cost $3.45. You have a total of 15 dimes and quarters.
Let d = the number of dimes you have.
Let q = the number of quarters you have.
Write a system of equations that models the information given above.
Solve the system for the number of dimes and quarters you have. You may want to solve this by graphing.
Click here to see answer by rcmcc(152)  |
Question 57327: 3. An airplane flew 4 hours with a 25 mph tail wind. The return trip against the same wind took 5 hours. Find the speed of the airplane in still air. This similar to the current problem as you have to consider the 25 mph tailwind and headwind.
Let r = the rate or speed of the airplane in still air.
Let d = the distance
Write a system of equations for the airplane. One equation will be for the outbound trip with tailwind of 25 mph. The second equation will be for the return trip with headwind of 25 mph. Solve the system of equations for the speed of the airplane in still air.
Click here to see answer by stanbon(75887) |
Question 57315: 3. An airplane flew 4 hours with a 25 mph tail wind. The return trip against the same wind took 5 hours. Find the speed of the airplane in still air. This similar to the current problem as you have to consider the 25 mph tailwind and headwind.
Let r = the rate or speed of the airplane in still air.
Let d = the distance
Write a system of equations for the airplane. One equation will be for the outbound trip with tailwind of 25 mph. The second equation will be for the return trip with headwind of 25 mph. . Solve the system of equations for the speed of the airplane in still air.
Click here to see answer by stanbon(75887) |
Question 57332: The American Kennel Club recognizes 7 categories of dogs plus one for miscellaneous breeds. In 2002 Dual Championships were awarded to 141 dogs. Dual champions are dogs that show excellence in both breed standard and ability to perform the function for that breed. Out of those 141 dogs, one was awarded to a dog in the toy class and 3 to dogs in the herding breeds. The remaining Dual Championships were awarded to dogs in the sporting breeds and the hound breeds. There were 93 more Dual Championships awarded to dogs in the hound breeds than the sporting breeds. (Source: American Kennel Club)
Let s = number of sporting breeds awarded Dual Championships
Let h = number of hound breeds awarded Dual Championships.
1. Write a system of equations that could be used to determine the number of Dual Championships awarded to sporting breeds and hound breeds.
Click here to see answer by stanbon(75887) |
Question 58273: The length of a rectangle is 12 cm more than its width. A second rectangle is 3cm shorter in width and 5cm longer in length than the first rectangle, and has a perimeter of 68cm. What are the dimensions of this second rectangle.
So far, I got first rectangle is L=w+12 and then got confused. I know the second rectangle 2L+2W=68. This question is not from a textbook, but from a worksheet.
Click here to see answer by faceoff57(108)  |
Question 58294: Can someone help me on this problem?
I need to solve the following system by using either addition or substitution. If a unique solution does not exist, I have to state whether the system is dependent or inconsistent.
10x + 2y -= 7
y = -5x + 3
Thanks,
Ashley
Click here to see answer by venugopalramana(3286) |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400
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