Tutors Answer Your Questions about Systems-of-equations (FREE)
Question 370589: I have two problems each have three set of equations in them. The first problem is x+y+2z=5 x+y=5 x+3y+z=11 the next problem is 2x+2y+4z=10 3x+3y=15 4x+12y+4z=44. Now I have already solve for x,y,z for both of these problems but my next question was to find the diference between the two systems. Im not quite sure on what to do.
Click here to see answer by jim_thompson5910(35256)  |
Question 372765: A dehydrated patient needs a 2.6% saline IV. Unfortunately, the hospital only has bags of 8% and 2% saline solutions. How many liters of each solutions should be mixed together to yield 2 liters of the desired concentration.
Click here to see answer by josmiceli(19441)  |
Question 373304: Tyrone is twice as old as his daughter. In six years Tyrone's age will be three times what his daughter's age was six years ago. How old are they at present? (We have been using the sublimation method and the addition method.)
Click here to see answer by scott8148(6628)  |
Question 373868: Solve the system.
Log base x (2y) =3
Log base x (4y)=2
I did the change of x^3 = 2y then 2y = x^3 for the first equation. Then, I did the same for the second one. x^2 = 4y. I was trying to solve for y on the first one but I am confused now.
Thank you.
EC
Click here to see answer by josmiceli(19441) |
Question 375442: one thousand tickets were sold for a baseball game. There were one hundred more adult tickets than student tickets, and there were four times as many tickets sold to students as to children. How many of each type of ticket were sold?
Click here to see answer by ewatrrr(24785)  |
Question 375882: SOlve using the multiplication principle first, then use the elimination method:
7p+5q=2
8p-9q=17, I came up with p=1, q=1, however I plugged this into a different site to double check my work and was told something different.
Click here to see answer by Fombitz(32388)  |
Question 376791: Hi - my tutor is out of town and am stuck on this problem. Solve this sytem of equations for real number solutions: y=x^2-4 and x^2 = y^2 = 10 So far I have done this:
x^2 + y^2 = 10
-X^2 = y = -4
y^2 + y = 6
y^2 + y - 6 = 0
(y-2) (y + 3) = 0
y-2 = 0 y + 3 = 0
Y = 2 and y = -3
am now stuck
Thanks for your assistance
Carol
Click here to see answer by Alan3354(69443)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400
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