SOLUTION: Hello! I need help on solving these systems of equations, quadratic {{{9y^2+77x-190=0}}}, {{{14x^2-9y^2-7x-6=0}}}

Algebra ->  Systems-of-equations -> SOLUTION: Hello! I need help on solving these systems of equations, quadratic {{{9y^2+77x-190=0}}}, {{{14x^2-9y^2-7x-6=0}}}      Log On


   



Question 972410: Hello! I need help on solving these systems of equations, quadratic
9y%5E2%2B77x-190=0,
14x%5E2-9y%5E2-7x-6=0

Found 2 solutions by amarjeeth123, MathTherapy:
Answer by amarjeeth123(569) About Me  (Show Source):
You can put this solution on YOUR website!
9y^2+77x-190=0..........equation 1
14x^2-9y^2-7x-6=0.......equation 2
9y^2=190-77x............equation 3
Substituting equation 1 in 2 we get
14x^2-9y^2-7x-6=0
14x^2-190+77x-7x-6=0
14x^2+70x-196=0
x^2+5x-14=0
x^2+7x-2x-14=0
x(x+7)-2(x+7)=0
(x-2)(x+7)=0
x=2
Substituting in equation 1 we get,
9y^2+154-190=0
9y^2=36
y^2=4
y=2
x=2 and y=2 is the solution.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Hello! I need help on solving these systems of equations, quadratic
9y%5E2%2B77x-190=0,
14x%5E2-9y%5E2-7x-6=0
      9y%5E2+%2B+77x+-+190+=0+ ---- eq (i)
14x%5E2+-+9y%5E2+-++7x+-+6+=+0 ------- eq (ii)
14x%5E2+%2B+70x+-+196+=+0 ------- Adding eqs (ii) & (i)
14%28x%5E2+%2B+5x+-+14%29+=+14%280%29
x%5E2+%2B+5x+-+14+=+0
(x + 7)(x - 2) = 0
x + 7 = 0 OR x - 2 = 0
highlight_green%28system%28x+=+-+7_or%2Cx+=+2%29%29
If x = - 7
9y%5E2+%2B+77x+-+190+=+0 ---- eq (i)
9y%5E2+%2B+77%28-+7%29+-+190+=+0
9y%5E2+-+539+-+190+=+0
9y%5E2+-++729+=+0
9%28y%5E2+-+81%29+=+9%280%29
y%5E2+=+81
highlight_green%28system%28y+=+9_or%2Cy+=+-+9%29%29
Thus, we get: highlight_green%28system%28when_x+=+7%2Cy+=+0_or%2C+y+=+-+7%29%29
If x = 2
9y%5E2+%2B+77x+-+190+=+0 ---- eq (i)
9y%5E2+%2B+77%282%29+-+190+=+0
9y%5E2+%2B+154+-+190+=+0
9y%5E2+-++36+=+0
9%28y%5E2+-+4%29+=+9%280%29
y%5E2+=+4
highlight_green%28system%28y+=+2_or%2Cy+=+-+2%29%29
Thus, we get: highlight_green%28system%28when_x+=+2%2Cy+=+2_or%2C+y+=+-+2%29%29