SOLUTION: Six times ashleys age plus two times sydney's age equals 38. sydney's age is also three more than five times ashley's age/ how old is sydney?

Algebra ->  Systems-of-equations -> SOLUTION: Six times ashleys age plus two times sydney's age equals 38. sydney's age is also three more than five times ashley's age/ how old is sydney?      Log On


   



Question 954565: Six times ashleys age plus two times sydney's age equals 38. sydney's age is also three more than five times ashley's age/ how old is sydney?
Answer by aYummyNoodle(10) About Me  (Show Source):
You can put this solution on YOUR website!
let x = Ashley's age.
let y = Sydney's age.
We can put the words into equations.
6x%2B2y=38 and
y=5x%2B3.
There are many different ways of solving systems of linear equations which are graphing, substitution, and elimination. For this system I will use substitution and elimination.
SUBSTITUTION:
In the second equation, y is already isolated so we can just plug it in to the first equation:
6x%2B2%285x%2B3%29=38
6x%2B10x%2B6=38
16x%2B6=38
16x=32
x=2
Now that we know that x is 2, we can plug it in to the second equation:
y=5%282%29%2B3
y=10%2B3
y=13.
After finding out that x is 2 and y is 13, we can write it in an ordered pair or a complete sentence.
(2,13) or:
Ashley is 2 years old and Sydney is 13 years old.
ELIMINATION:
In elimination, we need to line the variables and coefficients up, so
6x%2B2y=38 and
-5x%2By=3.
Multiply the second equation by 2 to get:
-10x%2B2y=6.
By subtracting one equation from another, we can eliminate the y's and get:
16x=32
x=2.
So Ashley is 2 years old.
Plugging x back into the second equation, we get:
-5%282%29%2By=3
-10%2By=3
y=13.
So Sydney is 13 years old.
Once again, Ashley is 2 years old and Sydney is 13 years old.