SOLUTION: Figure A is one square surrounded by 4 triangles (one on each side of the square). Figure B has two squares right next to each other with two triangles (one on either side). Each s

Algebra ->  Systems-of-equations -> SOLUTION: Figure A is one square surrounded by 4 triangles (one on each side of the square). Figure B has two squares right next to each other with two triangles (one on either side). Each s      Log On


   

Question 954533: Figure A is one square surrounded by 4 triangles (one on each side of the square). Figure B has two squares right next to each other with two triangles (one on either side). Each square has the same area. Each triangle has the same area. The total area of Figure A is 141 cm^2. The total area of Figure B is 192 cm^2. Please find the area of each and triangle.
Answer by macston(5194) About Me  (Show Source):
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s=square; t=triangle
1s+4t=141cm^2
s=141cm^2-4t
2s+2t=192cm^2 Substitute for s.
2(141cm^2-4t)+2t=192cm^2
282cm^2-8t+2t=192cm^2 Subtract 192cm^2 from each side.
90cm^2-6t=0 Add 6t to each side.
90cm^2=6t Divide each side by 6.
15cm^2=t ANSWER 1; The area of the triangles is 15 square centimeters.
s=141cm^2-4t
s=141cm^2-4(15cm^2)
s=141cm^2-60cm^2
s=81cm^2 ANSWER 2: The area of each square is 81 square centimeters.
CHECK:
2s+2t=192cm^2
2(81cm^2)+2(15cm^2)=192cm^2
162cm^2+30cm^2=192cm^2
192cm^2=192cm^2