SOLUTION: Can i please have help with: 1/3x + y = 5/3 and x^2 + y^2 = 25 I need to solve the system by way of substitution.

Algebra ->  Systems-of-equations -> SOLUTION: Can i please have help with: 1/3x + y = 5/3 and x^2 + y^2 = 25 I need to solve the system by way of substitution.      Log On


   



Question 927526: Can i please have help with: 1/3x + y = 5/3 and x^2 + y^2 = 25 I need to solve the system by way of substitution.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
y=-x%2F3%2B5%2F3
-
x%5E2%2B%28-x%2F3%29%2B5%2F3%29%5E2=25
x%5E2%2Bx%5E2%2F9-x%2A5%2F3-x%2A5%2F3%2B25%2F9=25
x%5E2%2Bx%5E2%2F9-10x%2F3=25-25%2F9
9x%5E2%2Bx%5E2-30x=25%2A9-25
10x%5E2-30x=200
x%5E2-3x=20
x%5E2-3x-20=0
-
x=%283%2B-+sqrt%289%2B4%2A20%29%29%2F2
highlight%28x=%283%2B-+sqrt%2889%29%29%2F2%29, and use this to evaluate y.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Can i please have help with: 1/3x + y = 5/3 and x^2 + y^2 = 25 I need to solve the system by way of substitution.
%281%2F3%29x+%2B+y+=+5%2F3_____y+=+5%2F3+-+%281%2F3%29x ------- eq (i)
x%5E2+%2B+y%5E2+=+25 ------- eq (ii)
Substitute 5%2F3+-+%281%2F3%29x for y in eq (ii)
Solving for x will result in:
highlight_green%28system+%28x+=+5_when%2C+y+=+0%29%29
OR
highlight_green%28system+%28x+=+-+4_when%2C+y+=+3%29%29
You can do the check!!

===================
If you need a complete and detailed solution, let me know!!
Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
Further help is available, online or in-person, for a fee, obviously.
For FREE info and answers to questions about the ASVAB exam, the NYS 3 – 8 city/state wide exams,GENERAL
MATH and HOMEWORK QUESTIONS, or MATH QUESTIONS related to the Regents Integrated Algebra,
Regents Geometry, Regents Algebra 2/Trigonometry, SHSAT, COOP/HSPT/TACHS, PSAT, SAT, ACT, SSAT/ISEE,
GRE, CLEP, and the TASC/GED, you can visit: http://asvabstudyzone.freeforums.net/.