SOLUTION: x^2+y^2=12 y^2=4x

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Question 925625: x^2+y^2=12
y^2=4x
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Substituting,
x%5E2%2B4x=12
x%5E2%2B4x-12=0
%28x%2B6%29%28x-2%29=0
Two solutions:
x%2B6=0
x=-6
y%5E2=-24
No real y solutions.
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x-2=0
x=2
Then,
y%5E2=8
y=0+%2B-+sqrt%288%29
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(2,sqrt%288%29)
(2,-sqrt%288%29)
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