SOLUTION: Solve each system algebraically. Explain why you chose the method you used.
x^2-48/9x+1/3y+1/3=0
-5/4x^2-3/2x+1/4y-1/2=0
Thankkk youuu :DDDD
Algebra ->
Systems-of-equations
-> SOLUTION: Solve each system algebraically. Explain why you chose the method you used.
x^2-48/9x+1/3y+1/3=0
-5/4x^2-3/2x+1/4y-1/2=0
Thankkk youuu :DDDD
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Question 878182: Solve each system algebraically. Explain why you chose the method you used.
x^2-48/9x+1/3y+1/3=0
-5/4x^2-3/2x+1/4y-1/2=0
Thankkk youuu :DDDD Found 2 solutions by Edwin McCravy, AnlytcPhil:Answer by Edwin McCravy(20056) (Show Source):
Sorry, there is no equal sign in the second one, so it
isn't an equation. Also there is no x term either but two number
terms, -3/2 and -1/2. I think you meant one of those to
have an x by it right? Type it carefully and correctly in the
thank-you note and I'll get back to you.
Edwin
I just guessed and put in an x and an equal sign in the second one.
Reduce the fraction to
Multiply the first one through by 3 and the
second one through by 4
Solve each for y:
St the right sides equal
Get 0 on the left side:
Factor the right side:
2x-1 = 0; 4x-3 = 0
2x = 1 4x = 3
x = ; x =
Substituting x = in
So one solution is (x,y) =
-----
Substituting x = in
So the other solution is (x,y) =
Edwin
