SOLUTION: how many solutions are for y + 3x = 2 and 2y - 4 = -6x ?
one solution, no solution, infinite solutions, cannot be determined
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-> SOLUTION: how many solutions are for y + 3x = 2 and 2y - 4 = -6x ?
one solution, no solution, infinite solutions, cannot be determined
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Question 868380: how many solutions are for y + 3x = 2 and 2y - 4 = -6x ?
one solution, no solution, infinite solutions, cannot be determined Answer by MathLover1(20849) (Show Source):
In order to graph these equations, we need to solve for y for each equation.
So let's solve for y on the first equation
Start with the given equation
Subtract from both sides
Rearrange the equation
Divide both sides by
Break up the fraction
Reduce
Now lets graph (note: if you need help with graphing, check out this solver)
Graph of
So let's solve for y on the second equation
Start with the given equation
Subtract from both sides
Rearrange the equation
Divide both sides by
Break up the fraction
Reduce
Now lets add the graph of to our first plot to get:
Graph of (red) and (green)
From the graph, we can see that the two lines are identical (one lies perfectly on top of the other) and intersect at all points of both lines. So there are an infinite number of solutions and the system is dependent.