SOLUTION: Solve the following systems a) y + 3 = 2x b) x^2 + 2xy = 1 Can you please help me out? Thanks so much in advance:)

Algebra ->  Systems-of-equations -> SOLUTION: Solve the following systems a) y + 3 = 2x b) x^2 + 2xy = 1 Can you please help me out? Thanks so much in advance:)       Log On


   

Question 867540: Solve the following systems
a) y + 3 = 2x
b) x^2 + 2xy = 1
Can you please help me out? Thanks so much in advance:)

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Some help is this:

(a) gives you y=2x-3. Substitute in (b) and you have,
x%5E2%2B2x%282x-3%29=1
simplifying to...
x%5E2%2B4x%5E2-6x=1
5x%5E2-6x-1=0.
Can you factor this and find x values? If not factorable, you can use the general solution of a quadratic equation and find the x values. Use them to get the corresponding y values.


(5x 1)(x 1)... NOT factorable.
x=%286%2B-+sqrt%28%28-6%29%5E2-4%2A5%2A%28-1%29%29%29%2F%282%2A5%29