SOLUTION: Solve this system of equations: y=x^2-2x-1 y=-x^2+4x-1
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Question 866293
:
Solve this system of equations:
y=x^2-2x-1
y=-x^2+4x-1
Answer by
farbonara(13)
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y=x^2-2x-1 ---(1)
y=-x^2+4x-1 ---(2)
(1)=(2)
x^2-2x-1=-x^2+4x-1
2x^2-6x=0
x^2-3x=0
(x)(x-3)=0
x=0 or x=3
Using (1),
When x=0,y=-1
When x=3,y=2