SOLUTION: System of equations. How do I solve this: 2x+4y+z=-3 3x-4y-z=-22 2x+y+2z=-3 I tried with 1 and 2 eliminating y and Z, but got stuck on how to find y and z. Thank you much

Algebra ->  Systems-of-equations -> SOLUTION: System of equations. How do I solve this: 2x+4y+z=-3 3x-4y-z=-22 2x+y+2z=-3 I tried with 1 and 2 eliminating y and Z, but got stuck on how to find y and z. Thank you much      Log On


   

Question 861065: System of equations.
How do I solve this:
2x+4y+z=-3
3x-4y-z=-22
2x+y+2z=-3
I tried with 1 and 2 eliminating y and Z, but got stuck on how to find y and z.
Thank you much!
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

2x+4y+z=-3

3x-4y-z=-22  ++highlight_green%28x+=+-5%29+ 

3x-4y-z=-22    |multiplying by2 added to second

2x+y+2z=-3

8x - 7y = -47 

-40 - 7y = -47 

   -7y = -7, ++highlight_green%28y+=+1%29+ 

2x+4y+z=-3

 -10 + 4 + z = -3

           z = 3

x=-5, y=1, and z=3