SOLUTION: How are you suppose to cancel out ? (4x+2y=66) (12x+8y=220)

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Question 837383: How are you suppose to cancel out ?
(4x+2y=66)
(12x+8y=220)
Found 2 solutions by Fombitz, mxgirl22:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
How about multiplying the first eq. by (-3) and adding to the second to eliminate x.
-12x-6y%2B12x%2B8y=-198%2B220
2y=22
y=11
Then use either equation to solve for x.
4x%2B22=66
4x=44
x=11
You could also have reduced first.
2x%2By=33 Divide both sides by 2.
3x%2B2y=55 Divide both sides by 4.

Answer by mxgirl22(39) About Me  (Show Source):
You can put this solution on YOUR website!

1.) (4x+2y=66)
2.) (12x+8y=220)

I'm assuming you mean solve for x and y.

1st) I can see x's will be easy to cancel out. So use -3 to make 4x into -12x. You need to multiply everything in equation 1.) by -3.
1.) -3(4x+2y=66)
2.) (12x+8y=220)
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-12x-6y=-198 <---This will be your new #1
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2nd) Combine.
1.) -12x-6y=-198
2.) 12x+8y=220
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2y=22
2y/2=22/2

y=11 <----- Solution for y
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3rd) Solve for x. Plug in y=11. Use one of the original equations.
1.) 4x+2y=66
4x+2(11)=66
4x+22=66
4x+22-22=66-22
4x=44
4x/4=44/4

x=11 <----- Solution for x
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4th) Just for safety...I'm going to plug in the values I found (x=11 and y=11) into equation 2.
2.) 12x+8y=220
12(11)+8(11)=220
132+88=220
220=220

And it checks!

So answer is: x=11 and y=11