Question 73692: Hi - could someone please provide some help on this one? Thanks so very much in advance!
One train leaves a station heading due west. Two hours later a second train leaves the same station heading due east. The second train is traveling 15mi/h faster than the first. Six hours after the second train leaves, the two trains are 580 miles apart. Find the rate at which each train is traveling.
(I think I am getting confused by the fact that the second train leaves 2 hours after the first rather than at the same time)
Thanks again for any help on this one :>)
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! One train leaves a station heading due west. Two hours later a second train leaves the same station heading due east. The second train is traveling 15mi/h faster than the first. Six hours after the second train leaves, the two trains are 580 miles apart. Find the rate at which each train is traveling.
:
Let s = speed of train 1
(s+15) = speed of train 2
:
Since train 1 started two hours earlier, it has been traveling for 8 hrs;
While the train 2 has been traveling 6 hrs:
:
Dist = time * speed
:
Train 1 dist + train 2 dist = 580
8s + 6(s+15) = 580
:
8s + 6s + 90 = 580
:
14s = 580 - 90
:
14s = 490
:
s = 490/14
:
s = 35 mph, train 1's speed
:
Train 2's speed = 35 + 15 = 50 mph
:
:
Check:
8*35 + 6*50 =
280 + 300 = 580
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