SOLUTION: Kay wants a rectangular area in the greenhouse reserved for African Violets. She says the width of the area must be one foot less than the length. She also says the area must be at
Algebra ->
Systems-of-equations
-> SOLUTION: Kay wants a rectangular area in the greenhouse reserved for African Violets. She says the width of the area must be one foot less than the length. She also says the area must be at
Log On
Question 66528: Kay wants a rectangular area in the greenhouse reserved for African Violets. She says the width of the area must be one foot less than the length. She also says the area must be atleast 12 square feet. What widths would satisfy Kay's requirements? Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! length = l
width = l - 1
width*length = area
l(l - 1) >= 12
l^2 - l - 12 >= 0
(l^2 - 4l) + (3l - 12) >= 0
l(l - 4) + 3(l - 4) >= 0
(l + 3)(l - 4) >= 0
<=====(-3]-------[4)====>
Length can not be negative, so: while
(