SOLUTION: Please help use Cramer's rule to solve the linear system. ( 3x-2y-z=3 x+2y-5z=-31 -7x+y+z=25

Algebra ->  Systems-of-equations -> SOLUTION: Please help use Cramer's rule to solve the linear system. ( 3x-2y-z=3 x+2y-5z=-31 -7x+y+z=25      Log On


   



Question 618812: Please help use Cramer's rule to solve the linear system.
( 3x-2y-z=3
x+2y-5z=-31
-7x+y+z=25

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Please help use Cramer's rule to solve the linear system.
3x-2y-z=3
x+2y-5z=-31
-7x+y+z=25
x= -145/31 y = -288/31 z = 48/31)
Solved by pluggable solver: Using Cramer's Rule to Solve Systems with 3 variables







First let A=%28matrix%283%2C3%2C3%2C-2%2C-1%2C1%2C2%2C-5%2C-7%2C1%2C1%29%29. This is the matrix formed by the coefficients of the given system of equations.


Take note that the right hand values of the system are 3, -31, and 25 and they are highlighted here:




These values are important as they will be used to replace the columns of the matrix A.




Now let's calculate the the determinant of the matrix A to get abs%28A%29=-62. To save space, I'm not showing the calculations for the determinant. However, if you need help with calculating the determinant of the matrix A, check out this solver.



Notation note: abs%28A%29 denotes the determinant of the matrix A.



---------------------------------------------------------



Now replace the first column of A (that corresponds to the variable 'x') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5Bx%5D (since we're replacing the 'x' column so to speak).






Now compute the determinant of A%5Bx%5D to get abs%28A%5Bx%5D%29=290. Again, as a space saver, I didn't include the calculations of the determinant. Check out this solver to see how to find this determinant.



To find the first solution, simply divide the determinant of A%5Bx%5D by the determinant of A to get: x=%28abs%28A%5Bx%5D%29%29%2F%28abs%28A%29%29=%28290%29%2F%28-62%29=-145%2F31



So the first solution is x=-145%2F31




---------------------------------------------------------


We'll follow the same basic idea to find the other two solutions. Let's reset by letting A=%28matrix%283%2C3%2C3%2C-2%2C-1%2C1%2C2%2C-5%2C-7%2C1%2C1%29%29 again (this is the coefficient matrix).




Now replace the second column of A (that corresponds to the variable 'y') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5By%5D (since we're replacing the 'y' column in a way).






Now compute the determinant of A%5By%5D to get abs%28A%5By%5D%29=576.



To find the second solution, divide the determinant of A%5By%5D by the determinant of A to get: y=%28abs%28A%5By%5D%29%29%2F%28abs%28A%29%29=%28576%29%2F%28-62%29=-288%2F31



So the second solution is y=-288%2F31




---------------------------------------------------------





Let's reset again by letting A=%28matrix%283%2C3%2C3%2C-2%2C-1%2C1%2C2%2C-5%2C-7%2C1%2C1%29%29 which is the coefficient matrix.



Replace the third column of A (that corresponds to the variable 'z') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5Bz%5D






Now compute the determinant of A%5Bz%5D to get abs%28A%5Bz%5D%29=-96.



To find the third solution, divide the determinant of A%5Bz%5D by the determinant of A to get: z=%28abs%28A%5Bz%5D%29%29%2F%28abs%28A%29%29=%28-96%29%2F%28-62%29=48%2F31



So the third solution is z=48%2F31




====================================================================================

Final Answer:




So the three solutions are x=-145%2F31, y=-288%2F31, and z=48%2F31 giving the ordered triple (-145/31, -288/31, 48/31)




Note: there is a lot of work that is hidden in finding the determinants. Take a look at this 3x3 Determinant Solver to see how to get each determinant.